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Oct 11, 2021 at 7:43 comment added Tony Huynh It seems as if the case that $a$ is an internal vertex of the last ear and $b \in V(G') \setminus \{u\}$ needs more details (which I didn't write down). So, the proofs are probably the same length.
Oct 11, 2021 at 7:05 comment added okw1124 I think our proofs have exactly the same essence. In fact, 'oriented path' in my proof is the result of your induction. But your one is much shorter, and looks nice! Thanks a lot.
Oct 10, 2021 at 4:23 vote accept okw1124
Oct 8, 2021 at 14:49 history edited Tony Huynh CC BY-SA 4.0
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Oct 8, 2021 at 14:41 history undeleted Tony Huynh
Oct 8, 2021 at 14:41 history edited Tony Huynh CC BY-SA 4.0
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Oct 8, 2021 at 5:34 history deleted Tony Huynh via Vote
Oct 8, 2021 at 3:20 comment added okw1124 I think, maybe, I found a proper algorithm to draw such two trees. I will upload the sketch of my proof as soon as possible.
Oct 8, 2021 at 2:47 review Low quality posts
Oct 8, 2021 at 5:43
Oct 8, 2021 at 2:47 history edited Tony Huynh CC BY-SA 4.0
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Oct 8, 2021 at 1:21 comment added okw1124 In addition, with my brief guess, if so, one of $T_1$ and $T_2$ must have a cycle.
Oct 8, 2021 at 1:17 comment added okw1124 But if each of $ux_1$ path intersects with both of $ux_2$ paths, can we say $ux_i$ paths are internally-disjoint?
Oct 8, 2021 at 1:14 history edited Tony Huynh CC BY-SA 4.0
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Oct 8, 2021 at 1:08 history answered Tony Huynh CC BY-SA 4.0