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Jan 18, 2022 at 7:24 history edited YCor CC BY-SA 4.0
moved correction notice to the end since now inessential
Oct 30, 2021 at 17:10 comment added Brauer Suzuki This is a theorem of [J. S. Rose, Splitting properties of group extensions, Proc. London Math. Soc. (3) 22 (1971), 1–23].
Oct 8, 2021 at 8:12 comment added YCor @MarianoSuárez-Álvarez This is correct and there were explicit instances of my previous construction which provided a split extension, contrary to my claim. I have therefore rewritten the proof, being more careful in the embedding into a group $S$.
Oct 8, 2021 at 8:11 history undeleted YCor
Oct 8, 2021 at 8:10 history edited YCor CC BY-SA 4.0
rewrote proof
Oct 8, 2021 at 8:03 history edited YCor CC BY-SA 4.0
rewrote proof
Oct 8, 2021 at 7:22 history edited YCor CC BY-SA 4.0
explained mistake
Oct 8, 2021 at 7:07 history deleted YCor via Vote
Oct 8, 2021 at 5:59 comment added Mariano Suárez-Álvarez I sat down to write this out in detail. In the second paragraph, certainly the centralizer of $G$ in $G\rtimes L$ contains $Z\rtimes C_L(G)$, but why is it equal to it? An element $(g,l)$ in $G\rtimes L$ such that $l$ acts on $G$ as the inner automorphism $g^{-1}(?)g$ is also in the cetralizer :-1
Oct 7, 2021 at 22:05 history edited YCor CC BY-SA 4.0
fixed typo
Oct 7, 2021 at 21:53 history edited LSpice CC BY-SA 4.0
Missing space
Oct 7, 2021 at 21:53 comment added LSpice When you say "the semidirect product $A^2 \rtimes \langle u\rangle$ contains $Z \times \{0\}$", should it be ""contains $A \times \{0\}$" (presumably embedded as $A \times \{0\} \subseteq A^2 \to A^2 \rtimes \langle u\rangle$)?
Oct 7, 2021 at 20:02 comment added Mariano Suárez-Álvarez I've been googling for a while, actually! :-) The edit is just what I was looking for, thanks.
Oct 7, 2021 at 20:01 comment added YCor @MarianoSuárez-Álvarez This probably appears somewhere in MO and in the literature, I could prove it (using choice) but I gave an easy choice-free proof of a weaker statement which is enough.
Oct 7, 2021 at 20:00 history edited YCor CC BY-SA 4.0
added proof of embedding
Oct 7, 2021 at 19:12 comment added Mariano Suárez-Álvarez Thanks! Do you have a reference for the embedding of the Z into the center of a perfect group?
Oct 7, 2021 at 9:52 history answered YCor CC BY-SA 4.0