Skip to main content
7 events
when toggle format what by license comment
Oct 2, 2010 at 7:49 vote accept mediocrates
Sep 30, 2010 at 9:53 comment added user5117 Just for completeness, let me mention that these groups are easy to compute for all blowups of P^2, which includes the case of cubic surfaces. Result: Pic^0 is always trivial, and Pic = NS is always free abelian, with rank increasing by 1 each time you blow up.
Sep 30, 2010 at 9:08 comment added Emerton The case of cubic surfaces is also explained in Chapter 5 of Hartshorne. (More precisely, the Pic is computed there; I forget whether Hartshorne says anything about NS, although of course in this case they are equal.)
Sep 30, 2010 at 3:31 comment added Pete L. Clark Welcome to MO, Professor Zarhin.
Sep 30, 2010 at 3:31 history edited Pete L. Clark CC BY-SA 2.5
cosmetic improvements
Sep 30, 2010 at 1:22 history edited Yuri Zarhin CC BY-SA 2.5
corrected typo
Sep 30, 2010 at 1:12 history answered Yuri Zarhin CC BY-SA 2.5