Timeline for Sufficient conditions for the covering dimension and large inductive dimension of compact Hausdorff spaces to coincide
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Oct 9, 2021 at 18:05 | vote | accept | Robert Thingum | ||
| Oct 8, 2021 at 7:32 | answer | added | KP Hart | timeline score: 1 | |
| Oct 7, 2021 at 21:33 | comment | added | Henno Brandsma | Engelking has a compact Hausdorff example by Lokucievskii that has $\dim(X)=1=\operatorname{ind}(X) < 2 = \operatorname{Ind}(X)$. | |
| Oct 6, 2021 at 17:32 | comment | added | Robert Thingum | It looks like one such condition is that $dim(X)\leq n$ and there is either a metrizable space $Y$ and a continuous $f:X\rightarrow Y$ such that $dim(f)=0$ or else a perfectly zero dimensional space $Z$ and a continuous closed surjection $f:Z\rightarrow X$ such that the preimage of any $x\in X$ has at most $n+1$ points in $Z$. | |
| Oct 6, 2021 at 15:58 | history | edited | Robert Thingum | CC BY-SA 4.0 |
Added link to russian paper
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| Oct 6, 2021 at 14:34 | history | edited | Robert Thingum | CC BY-SA 4.0 |
general edits
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| Oct 6, 2021 at 12:30 | history | edited | YCor | CC BY-SA 4.0 |
formatting
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| Oct 6, 2021 at 11:59 | history | edited | Robert Thingum | CC BY-SA 4.0 |
Fixed a reference
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| Oct 6, 2021 at 11:41 | history | edited | Robert Thingum | CC BY-SA 4.0 |
Clarified question.
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| Oct 6, 2021 at 8:50 | history | asked | Robert Thingum | CC BY-SA 4.0 |