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Oct 11, 2021 at 15:14 vote accept Adrien MORIN
Oct 5, 2021 at 16:32 comment added Dmitri Pavlov @AdrienMORIN: Yes, the underlying object of Q is cofibrant as an object of M.
Oct 5, 2021 at 16:32 history edited Dmitri Pavlov CC BY-SA 4.0
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Oct 5, 2021 at 16:32 comment added Dmitri Pavlov @AdrienMORIN: If you have two cofibrant replacements Q and Q' of the monoid 1 in Mon(M), they are connected by a zigzag of weak equivalences Q→Q''←Q' in Mon(M). This zigzag induces a zigzag of weak equivalences of lax monoidal functors, as constructed in the answer.
Oct 5, 2021 at 14:47 comment added Adrien MORIN Could you comment a bit about the last part of my question, i.e. whether the derived structures one obtains through different cofibrant replacements of 1 in Mon(M) are essentially the same ? I suppose it somehow comes from the "homotopical uniqueness" of cofibrant replacements ?
Oct 5, 2021 at 14:19 comment added Adrien MORIN Do you mean "the underlying object $Q$ is a cofibrant object of $M$" ?
Oct 4, 2021 at 17:01 history answered Dmitri Pavlov CC BY-SA 4.0