Timeline for Closed form for odd part of Bernoulli Polynomial generating function, $\sum_{k=0}^{\infty}B_{2k+1}(x)\frac{t^{2k+1}}{(2k+1)!}$ [closed]
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Oct 4, 2021 at 10:32 | history | closed |
Alexandre Eremenko Stopple Alexey Ustinov Daniele Tampieri Nemo |
Needs details or clarity | |
| Oct 4, 2021 at 4:58 | comment | added | Hjalmar Rosengren | The odd part of the series can be written as $$\frac{t\sinh(t(x-1/2))}{2\sinh(t/2)}.$$ Is this all that you are asking? | |
| Oct 3, 2021 at 23:27 | vote | accept | Milo Moses | ||
| Oct 3, 2021 at 23:27 | history | edited | Milo Moses | CC BY-SA 4.0 |
edited title
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| Oct 3, 2021 at 22:18 | review | Close votes | |||
| Oct 4, 2021 at 10:37 | |||||
| Oct 3, 2021 at 22:01 | answer | added | Ira Gessel | timeline score: 2 | |
| Oct 3, 2021 at 21:11 | comment | added | Timothy Budd | The sums in the title and the text are different. I suspect the one in the title is the correct one, since the other one is just the odd part of the first display? | |
| Oct 3, 2021 at 21:10 | comment | added | Pietro Majer | Given the above gf of the Bernoully polynomials $F(x,t)$, why the odd part wrto t isn't just $$\mathcal G(x,t)=\frac12\Big( F(x,t)-F(x,-t)\Big)$$ ? | |
| Oct 3, 2021 at 20:01 | history | asked | Milo Moses | CC BY-SA 4.0 |