Timeline for Does the inverse Laplace transform of the square root exist?
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| Oct 1, 2021 at 18:01 | history | edited | Anixx | CC BY-SA 4.0 |
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| Oct 1, 2021 at 17:52 | comment | added | Anixx | @CarloBeenakker I have added an alternative derivation. | |
| Oct 1, 2021 at 17:51 | history | edited | Anixx | CC BY-SA 4.0 |
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| Oct 1, 2021 at 16:03 | comment | added | Anixx | @CarloBeenakker actually, the integral diverges if you integrate the Hadamard finite part. If you integrate the generalized function, including $0^+$, the integral converges. | |
| Oct 1, 2021 at 15:55 | history | edited | Anixx | CC BY-SA 4.0 |
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| Oct 1, 2021 at 12:25 | history | edited | Anixx | CC BY-SA 4.0 |
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| Oct 1, 2021 at 12:24 | comment | added | Anixx | @CarloBeenakker I have added the term that makes the integral finite. Thank you for pointing this out. | |
| Oct 1, 2021 at 12:23 | history | undeleted | Anixx | ||
| Oct 1, 2021 at 12:21 | history | deleted | Anixx | via Vote | |
| Oct 1, 2021 at 12:18 | history | undeleted | Anixx | ||
| Oct 1, 2021 at 12:18 | history | edited | Anixx | CC BY-SA 4.0 |
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| Oct 1, 2021 at 12:09 | history | deleted | Anixx | via Vote | |
| Oct 1, 2021 at 11:28 | comment | added | Carlo Beenakker | but the Laplace transform of $1/x^{3/2}$ diverges at $x=0$ (the $p>-1$ condition mentioned by the OP). | |
| Oct 1, 2021 at 11:14 | history | answered | Anixx | CC BY-SA 4.0 |