Timeline for What is the integral representation of the exponential function $e^{1/t}$ on $(0,\infty)$?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 3, 2022 at 9:30 | vote | accept | qifeng618 | ||
| Oct 6, 2021 at 18:00 | answer | added | qifeng618 | timeline score: 1 | |
| Sep 28, 2021 at 15:14 | comment | added | qifeng618 | It seems that this question is much easy. Thank you very much. Do you have any idea about the question at math.stackexchange.com/q/4247090/945479? | |
| Sep 28, 2021 at 14:54 | comment | added | qifeng618 | @HarryWilson I think it should be acceptable. I need to carefully prove it. | |
| Sep 28, 2021 at 14:54 | comment | added | Carlo Beenakker | $\int_0^\infty I_0(2\sqrt{t})e^{-xt}\,dt=x^{-1}e^{1/x}$ avoids the delta function, at the expense of the $1/x$ prefactor. | |
| Sep 28, 2021 at 14:51 | comment | added | Harry Wilson | Is that not an acceptable solution? | |
| Sep 28, 2021 at 14:46 | comment | added | qifeng618 | @Negan By the software Mathematica, I got the solution $\delta (t)+\frac{I_1\left(2 \sqrt{t}\right)}{\sqrt{t}}$. | |
| Sep 28, 2021 at 14:41 | comment | added | Nemo | Can't one just use inverse Laplace transform? | |
| Sep 28, 2021 at 13:47 | history | edited | qifeng618 | CC BY-SA 4.0 |
edited title
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| Sep 28, 2021 at 13:26 | history | asked | qifeng618 | CC BY-SA 4.0 |