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Sep 23, 2021 at 16:48 comment added joro @KConrad In your example with $n^2$ I have the properties "never prime" and "always squareful", which would be an answer to the question.
Sep 23, 2021 at 0:24 comment added KConrad Those double zeros are artificial, because they are coming from an $L$-function that appears inside the zeta-function of $K$ with multiplicity greater than $1$. It's sort of like asking if the repeated prime factors in a perfect square $n^2$ for $n > 1$ could imply some property of prime numbers. What is interesting are higher-order (meaning not of order $1$) nontrivial zeros for an $L$-function that does not (or is at least not expected to) decompose into other $L$-functions; such phenomena do happen in the setting of the Birch and Swinnerton-Dyer conjecture.
Sep 22, 2021 at 21:48 answer added 2734364041 timeline score: 5
Sep 22, 2021 at 15:26 comment added user334725 For Q2, usually one considers primitive $L$-functions, and the only Dedekind $\zeta$-function that is primitive is that for the rationals. So the fact that $\zeta_K$ for general $K$ can have higher order zeros (due to primitive factors occurring with high multiplicity) is not so relevant.
Sep 22, 2021 at 15:13 history asked joro CC BY-SA 4.0