Timeline for Combining coefficients in a sum of inequalities
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Sep 20, 2021 at 20:32 | comment | added | darij grinberg | Pretty sure it's impossible. Just take $X_{2,1} = X_{3,2} = X_{1,3} = -2$ and $X_{1,2} = X_{2,3} = X_{3,1} = 1$. The $\beta_j^i$s are easily found, but the $\beta_j$s cannot exist. | |
| Sep 20, 2021 at 20:31 | comment | added | darij grinberg | So, for $U = \left\{1,2,3\right\}$, you are given that $\beta_2^1 X_{2,1} + \beta_3^1 X_{3, 1} > 0$ and cyclically, and you want to find $\beta_1, \beta_2, \beta_3$ (all $\beta$s are positive) such that $\beta_1\left(X_{1,2} + X_{1,3}\right) + \beta_2\left(X_{2,1} + X_{2,3}\right) + \beta_3\left(X_{3,1} + X_{3,2}\right) > 0$, right? | |
| S Sep 20, 2021 at 20:10 | review | First questions | |||
| Sep 20, 2021 at 20:21 | |||||
| S Sep 20, 2021 at 20:10 | history | asked | user379923 | CC BY-SA 4.0 |