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Sep 20, 2021 at 17:12 comment added Richard Lyons One interesting case occurs when $P$ admits a group of automorphisms which acts irreducibly on $P/Z(P)$ but trivially on $Z(P)$. Then for every maximal subgroup $M$ of $Z(P)$, $P/M$ is extraspecial (exercise). It follows that every nonlinear ordinary irreducible character of $P$ has degree $p^{m/2}$.
Sep 18, 2021 at 22:15 comment added Derek Holt Also I don't think the character degrees are a fixed function of $p$, $n$ and $m$. In the case $3^{2+4}$, in some examples there are $36$ of degree $3$ and $4$ of degree $9$, and in others there are $8$ of degree $9$.
Sep 18, 2021 at 22:00 comment added Derek Holt If $n>1$ then there cannot be any faithful irreducible (complex) representations because the centre is not cyclic.
Sep 18, 2021 at 21:14 history edited LSpice CC BY-SA 4.0
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S Sep 18, 2021 at 20:26 review First questions
Sep 19, 2021 at 2:17
S Sep 18, 2021 at 20:26 history asked Isaac CC BY-SA 4.0