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Sep 18, 2021 at 15:36 comment added Will Brian @AlexRavsky: OK. I think $\mathrm{cov}(\mathcal N)$ is true (and can be proved as I outlined in my comments on the question), but I don't think I'll have any time to write the details down today.
Sep 18, 2021 at 14:50 comment added Alex Ravsky Thanks for your answer. We introduce the cardinal $\mathfrak x$ as an auxilliary bound for $\mathrm{cov}(\mathcal A(\mathbb T))$. We hoped that $\mathfrak x$ can be helpful to obtain a new bound for $\mathrm{cov}(\mathcal A(\mathbb T))$, where $\mathfrak x$ is not used explicitly. Taras Banakh suggested to dismiss $\mathfrak x$ if it yields us no such bound. So, in particular, a suggested bound $\mathrm{cov}(\mathcal N)\le \mathfrak x$ is desirable for us, but not crucial.
Sep 18, 2021 at 14:24 history answered Will Brian CC BY-SA 4.0