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Sep 17, 2021 at 5:55 comment added Disen The definition in en.wikipedia.org/wiki/Diophantine_equation requires it to be polynomial. I don't mean $\Theta(p^2)$ I mean $\Omega(p^2)$ in Knuth's sense but since there is ambiguity about $\Omega$ I didn't want to use it and instead opted for "requires $O(p^2)$ time." Sorry for any confusion.
Sep 17, 2021 at 5:36 answer added Steven Stadnicki timeline score: 4
Sep 16, 2021 at 23:43 comment added Steven Stadnicki When you say 'diophantine equation' I presume you mean polynomial? (And presumably you mean $\Theta(p^2)$ rather than $O(p^2)$, since e.g. $\log p\in O(p^2)$). And for that matter, do you know of an example where the best known algorithms take even $\Omega(p)$ time? Elliptic curves, for instance, have much faster algorithms known...
Sep 16, 2021 at 20:10 history edited Disen CC BY-SA 4.0
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Sep 16, 2021 at 20:02 history edited Disen CC BY-SA 4.0
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S Sep 16, 2021 at 19:55 review First questions
Sep 16, 2021 at 21:40
S Sep 16, 2021 at 19:55 history asked Disen CC BY-SA 4.0