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Sep 16, 2021 at 18:43 comment added Gregory Arone If $p\circ s$ is freely homotopic to the identity then it is a weak homotopy equivalence, and therefore has a pointed homotopy inverse. Precomposing $s$ with this inverse will give you a pointed homotopy section. So it seems to me that what you are asking for is impossible.
Sep 16, 2021 at 16:29 comment added Tyrone Let $B$ be the comb space with its bad basepoint, let $E=\ast$, and let $p$ be the inclusion of the basepoint.
Sep 16, 2021 at 15:29 history asked Mark Grant CC BY-SA 4.0