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when toggle format what by license comment
Sep 16, 2021 at 9:42 history edited Daniel Loughran CC BY-SA 4.0
added 40 characters in body
Sep 16, 2021 at 9:40 comment added Daniel Loughran Yes quite, thanks!
Sep 16, 2021 at 9:25 comment added Piotr Achinger Minor point: I think it's $\mathbf{P}^1\times \mathbf{P}^1$ that specializes to a Hirzebruch surface, not $\mathbf{P}^2$ (wrong Picard number).
Sep 16, 2021 at 9:09 history answered Daniel Loughran CC BY-SA 4.0