Skip to main content
14 events
when toggle format what by license comment
Sep 16, 2021 at 10:27 vote accept Pedja
Sep 16, 2021 at 9:43 answer added Mastrem timeline score: 10
Sep 16, 2021 at 9:30 comment added Pedja @Carl-FredrikNybergBrodda en.wikipedia.org/wiki/…
Sep 16, 2021 at 9:18 comment added Mastrem Isn't the second series just $3\cdot L(1,\chi)$, where $\chi$ is the non-trivial Dirichlet character modulo $6$? And the product of the two series is $9\cdot \prod_{p\ge 5}(1-p^{-2})^{-1}=6\zeta(2)=\pi^2$?
Sep 16, 2021 at 9:14 comment added Carl-Fredrik Nyberg Brodda @PeđaTerzić Which formula of Euler's did you have in mind (if a specific one)?
Sep 16, 2021 at 8:59 comment added Sylvain JULIEN I think Ramanujan produced a formula along these lines, for expressions the product of which equals $\pi^2$.
Sep 16, 2021 at 8:58 comment added Sylvain JULIEN Perhaps one could take advantage of the fact that the product of the LHS equals $\pi^2$.
Sep 16, 2021 at 8:52 comment added Pedja @gmvh There is a similar series for $\pi$ in the literature given by Euler.
Sep 16, 2021 at 8:50 comment added gmvh So is there another reason besides the numerical coincidence to believe this conjecture?
Sep 16, 2021 at 8:49 comment added Pedja @gmvh Perhaps it converges very slowly.
Sep 16, 2021 at 8:48 comment added Pedja @FedorPetrov Right.
Sep 16, 2021 at 8:45 comment added gmvh The first one doesn't seem to be particularly close from the SageMath cell linked.
Sep 16, 2021 at 8:40 comment added Fedor Petrov you count prime divisors with multiplicity, right?
Sep 16, 2021 at 8:37 history asked Pedja CC BY-SA 4.0