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Sep 15, 2021 at 7:00 comment added juan For $n\ge2$ there are $n+2$ sets in this family, $n$ of them contains $1$, and $n\ge (n+2)/2$. So this case is trivial.
Sep 15, 2021 at 6:15 comment added mathworker21 i doubt this case is known
Sep 14, 2021 at 20:24 comment added mkultra This is a set of all subsets $A\subset U$, so that $|A|=n-1$
Sep 14, 2021 at 19:24 comment added JoshuaZ What do you mean by $\mathcal{P}_{n-1}(U)$?
Sep 14, 2021 at 19:19 history asked mkultra CC BY-SA 4.0