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Sep 11, 2021 at 16:57 vote accept asv
Sep 11, 2021 at 16:02 review Close votes
Sep 21, 2021 at 3:03
Sep 11, 2021 at 15:40 comment added Alexandre Eremenko Any harmonic function which vanishes on $\partial\Omega$ AND at $\infty$ is evidently zero. This follows from the Maximum Principle.
Sep 11, 2021 at 14:55 history edited Willie Wong
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Sep 11, 2021 at 14:53 answer added Willie Wong timeline score: 2
Sep 11, 2021 at 14:20 history edited asv CC BY-SA 4.0
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Sep 11, 2021 at 14:13 comment added asv @WillieWong: You are right, thanks. I edited the question.
Sep 11, 2021 at 14:12 history edited asv CC BY-SA 4.0
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Sep 11, 2021 at 14:06 comment added Willie Wong Without boundary conditions there is no rate that suffice. In $n = 3$ for example $\partial_1^m \frac1r$ is harmonic and decays like $r^{-1-m}$.
Sep 11, 2021 at 14:04 comment added asv @MichaelEngelhardt: well, there is a bounded smooth domain containing the ball, such that on its boundary the function vanishes.
Sep 11, 2021 at 13:40 comment added Michael Engelhardt You'd at least have to say something about the boundary conditions on the surface of the ball ...
Sep 11, 2021 at 12:47 history asked asv CC BY-SA 4.0