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Sep 9, 2021 at 15:43 comment added Aaron Meyerowitz That is probably all that matters. gaps $2,4,8$ should occur equally often but only half as frequency as gaps $6,12,18$ due to residue classes $\bmod 3.$
Sep 9, 2021 at 9:26 vote accept Sylvain JULIEN
Sep 9, 2021 at 9:24 comment added Sylvain JULIEN I décided to accept your answer, as it shows we need the sets of possible residue classes of $p$ mod the relevant prime to have the same cardinal. Those sets of residue classes with same cardinal may then play the role of analogues of conjugacy classes in Chebotarev's theorem.
Sep 9, 2021 at 9:20 vote accept Sylvain JULIEN
Sep 9, 2021 at 9:26
Sep 9, 2021 at 6:55 history edited Aaron Meyerowitz CC BY-SA 4.0
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Sep 9, 2021 at 6:27 history edited Aaron Meyerowitz CC BY-SA 4.0
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Sep 8, 2021 at 10:51 history edited Aaron Meyerowitz CC BY-SA 4.0
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Sep 8, 2021 at 10:10 history edited Aaron Meyerowitz CC BY-SA 4.0
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Sep 8, 2021 at 9:42 comment added Sylvain JULIEN Actually I think we should require that all iterates of a "good" permutation $\sigma$ preserve the admissibility, but it may not be enough.
Sep 8, 2021 at 9:29 comment added Sylvain JULIEN I don't think those make prime constellations as the diameter of the related $k$-tuples is not minimal. But your argument looks sound and there seems to be some subtlety I can't pinpoint yet.
Sep 8, 2021 at 9:14 history answered Aaron Meyerowitz CC BY-SA 4.0