Timeline for Value of divergent sum $\sum_{n=0}^\infty (-1)^n n^n$
Current License: CC BY-SA 4.0
18 events
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| Sep 24, 2021 at 4:00 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 24, 2021 at 3:30 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 23, 2021 at 13:25 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 23, 2021 at 12:48 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 23, 2021 at 12:39 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 21, 2021 at 17:47 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 9, 2021 at 23:39 | comment | added | Iosif Pinelis | @JorgeZuniga : Thank you for your response. | |
| Sep 9, 2021 at 0:01 | comment | added | Jorge Zuniga | Iosif, the derivative relationship 1 - t*dW0(t)/dt =1/(1+W0(t)) makes the trick. This sum is an excellent probe test for summation methods acting on alternating divergent series. | |
| Sep 8, 2021 at 14:01 | comment | added | Iosif Pinelis | I thought about this method, but did not know how to extend $\sum _{k=0}^{\infty } \frac{(-1)^k k^k t^k}{k!}$ analytically. How to prove that this sum is $1/(1+W_0(t))$? | |
| Sep 7, 2021 at 16:16 | comment | added | Caleb Briggs | I should add to this wonderful answer, that $$\int_0^\infty \frac{e^{-x}}{1+W_0(x)}dx = \int_1^\infty \frac{1}{x^x}$$ Which makes this answer answer very similar to form to the sophmore's dream | |
| Sep 7, 2021 at 6:23 | history | edited | Anixx | CC BY-SA 4.0 |
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| Sep 7, 2021 at 6:11 | history | edited | Anixx | CC BY-SA 4.0 |
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| Sep 7, 2021 at 4:39 | history | edited | Daniele Tampieri | CC BY-SA 4.0 |
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| Sep 7, 2021 at 3:21 | history | edited | Jorge Zuniga | CC BY-SA 4.0 |
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| Sep 7, 2021 at 3:17 | vote | accept | Caleb Briggs | ||
| Sep 7, 2021 at 3:17 | comment | added | Caleb Briggs | Wow! This is truly incredible-- thank you for this answer! | |
| S Sep 7, 2021 at 3:08 | review | First answers | |||
| Sep 7, 2021 at 4:40 | |||||
| S Sep 7, 2021 at 3:08 | history | answered | Jorge Zuniga | CC BY-SA 4.0 |