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Sep 24, 2021 at 1:33 vote accept Deyi Chen
Sep 24, 2021 at 1:04 answer added Zhi-Wei Sun timeline score: 4
Sep 10, 2021 at 16:20 comment added Zhi-Wei Sun The last determinant formula in my comment has been proved by graduate student Chen-Kai Ren.
Sep 8, 2021 at 5:42 history edited Deyi Chen CC BY-SA 4.0
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Sep 7, 2021 at 17:41 history edited Deyi Chen CC BY-SA 4.0
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Sep 7, 2021 at 17:28 history edited Deyi Chen CC BY-SA 4.0
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Sep 6, 2021 at 22:50 comment added Zhi-Wei Sun I consider the similar problem for determinants. I conjecture that if $n>1$ is odd then $$\det\left[\mathrm{sgn}\left(\sin\pi\frac{j+2k}n\right)\right]_{1\le j,k\le n-1}=(-1)^{(n^2-1)/8}.$$
Sep 6, 2021 at 18:33 comment added Zach Teitler That’s a very fun conjecture! To prove it, what have you tried so far?
Sep 6, 2021 at 17:43 history asked Deyi Chen CC BY-SA 4.0