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Sep 10, 2021 at 13:32 comment added Uri Bader Related: mathoverflow.net/q/269008/89334
Sep 7, 2021 at 22:09 vote accept Erik Walsberg
Sep 6, 2021 at 8:49 answer added YCor timeline score: 17
Sep 6, 2021 at 2:50 answer added Will Sawin timeline score: 30
Sep 6, 2021 at 0:15 comment added Will Sawin $SO(3)$ embeds into $SO_3(\mathbb C)$. Using choice, fix an isomorphism between $\mathbb C$ and $\overline{\mathbb Q_p}$, giving an isomorphism between $SO_3(\mathbb C)$ and $SO_3(\overline{\mathbb Q_p})$. Then doesn't $SO_3(\overline{\mathbb Q_p})$ act faithfully on $SO_3(\overline{\mathbb Q_p})/SO_3(\overline{\mathbb Z_p})$, which is countable because it is the union over all finite extensions $K_p$ of $\mathbb Q_p$ with ring of integers $\mathcal O_{K_p}$ of the countable $SO_3(K_p)/ SO_3(\mathcal O_{K_p})$?
Sep 6, 2021 at 0:01 history asked Erik Walsberg CC BY-SA 4.0