Timeline for Showing that $\sum_{n=0}^\infty (4n+1)q^{\left (\frac{4n+1}{2}\right)^2} - \sum_{n=1}^\infty (4n-1)q^{\left (\frac{4n-1}{2}\right)^2} \geq 0.1$
Current License: CC BY-SA 4.0
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Sep 10, 2021 at 18:05 | comment | added | J. Swail | Yes, I like the answer very much. Thanks a lot!! | |
Sep 10, 2021 at 18:05 | vote | accept | J. Swail | ||
Sep 10, 2021 at 0:21 | comment | added | Iosif Pinelis | @J.Swail : Are you satisfied with this answer? | |
Sep 5, 2021 at 3:24 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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Sep 5, 2021 at 2:59 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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Sep 5, 2021 at 2:43 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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Sep 5, 2021 at 1:53 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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Sep 5, 2021 at 1:44 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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Sep 5, 2021 at 1:39 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |