Timeline for Prove that the equation $2^a - 2^b - 1=3^c$ has no integral solution with $a,b\geq 3$
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 5, 2021 at 3:04 | vote | accept | Nya | ||
| Sep 5, 2021 at 1:21 | comment | added | GH from MO | @GerryMyerson: Those are the only two solutions, by Bennett's theorem: personal.math.ubc.ca/~bennett/B-CJM-Pillai.pdf | |
| Sep 5, 2021 at 0:56 | comment | added | Gerry Myerson | $b=1$ is clearly impossible, so we are left with $b=2$, $2^a-5=3^c$, which has (at least) the two solutions $8-5=3$ and $32-5=27$ (as noted by Andreas). Are there any more? | |
| Sep 5, 2021 at 0:21 | history | answered | GH from MO | CC BY-SA 4.0 |