Timeline for Subgroups of a group generated by a free semigroup
Current License: CC BY-SA 2.5
3 events
when toggle format | what | by | license | comment | |
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Nov 4, 2009 at 3:55 | comment | added | Autumn Kent | I guess I don't understand what "middle" means. | |
Nov 4, 2009 at 1:44 | comment | added | Autumn Kent | Oh, just take G = <g_1, g_2, . . .> to be the kernel of the map from <a,b> to the free abelian group on a and b. Then G has (P) and K' lies in G, and so K' has (P) as well. | |
Nov 4, 2009 at 1:20 | history | answered | Autumn Kent | CC BY-SA 2.5 |