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Aug 31, 2021 at 8:26 answer added Peter Taylor timeline score: 2
Aug 31, 2021 at 6:17 comment added Mohammad Ali Nematollahi @PeterTaylor Thank you. The value is about 4.95705. Can you tell me please how you calculated that?
Aug 30, 2021 at 16:18 comment added Peter Taylor The average value of $D(T)$ over all unlabelled trees on 240 vertices is $\tfrac{272563652060306897395747185358655803738754221966330221551036734394657565391873216737292786227592630120780361}{54985024966026897870269075763444229658301263057496157167354274092275126613889793234171034121437216543398430}$
Aug 26, 2021 at 7:40 answer added Gordon Royle timeline score: 3
Aug 26, 2021 at 7:28 comment added Peter Taylor cs.uwaterloo.ca/journals/JIS/cayley.html shows the technique applied to a different problem. I note (which I had forgotten) that it also suggests that it's often simpler to use the fact that a finite tree has either a centroid or a bicentroid.
Aug 26, 2021 at 5:23 comment added Mohammad Ali Nematollahi @PeterTaylor Can you give me an example?
Aug 26, 2021 at 5:21 comment added Mohammad Ali Nematollahi @Mike If the tree is of order $n$, by random tree, I mean a uniform spanning tree of $K_{n}$.
Aug 25, 2021 at 22:10 comment added Peter Taylor You can probably calculate exact values for question 2 for $n$ up to a few dozen by using the fact that a finite tree has either a centre or a bicentre.
Aug 25, 2021 at 20:54 comment added Mike what do you mean by "random" tree. From which probability space are the trees drawn?
Aug 23, 2021 at 14:08 comment added Mohammad Ali Nematollahi @DavidSheard Now mentioned in the qurstion.
Aug 23, 2021 at 14:07 history edited Mohammad Ali Nematollahi CC BY-SA 4.0
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Aug 23, 2021 at 14:04 comment added Mohammad Ali Nematollahi Yes, the trees are finite.
Aug 23, 2021 at 13:58 comment added David Sheard Are your trees finite? If not then $D(T)$ could be 0, take $\mathbb{R}$ as an example, or unbounded if $T$ is not locally finite.
Aug 23, 2021 at 10:20 history asked Mohammad Ali Nematollahi CC BY-SA 4.0