Timeline for Methods to bound the number of solutions to $x^x \equiv 1 \mod p$ with $1 \le x \le p$
Current License: CC BY-SA 4.0
5 events
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Aug 21, 2021 at 10:51 | comment | added | mathworker21 | thanks. By the way, the reference in the other answer gets to $3/7$ in (essentially) the same way and then pushes past that by using bounds for exponential sums over multiplicative subgroups. | |
Aug 21, 2021 at 10:38 | comment | added | Random | @mathworker21 Oops, you're right. Fixed that | |
Aug 21, 2021 at 10:37 | history | edited | Random | CC BY-SA 4.0 |
3/8 to 3/7
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Aug 21, 2021 at 9:29 | comment | added | mathworker21 | $+1$. "As stated in the post, it is sufficient to show $|A_d| \le p^{3/8+\epsilon}$". Do you mean $p^{3/7+\epsilon}$? | |
Aug 21, 2021 at 1:27 | history | answered | Random | CC BY-SA 4.0 |