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Aug 23, 2021 at 3:08 comment added Emily @MarcHoyois Oh right, I completely misunderstood Dmitri's answer. Also, the statement you mentioned about homotopy dimension goes precisely in the direction I wanted. Thanks!
Aug 21, 2021 at 9:25 history edited Marc Hoyois CC BY-SA 4.0
fixed inequality
Aug 21, 2021 at 7:58 comment added Marc Hoyois $n$ became $-n$ in the middle of my previous comment, but hopefully what I meant is clear.
Aug 21, 2021 at 7:47 comment added Marc Hoyois $n$-connective spectra are reduced excisive functors $\mathcal S^\mathrm{fin}_*\to\mathcal S$ that increase connectivity by at least $n$. A statement which I think goes in the direction you want is that such functors are determined by their restriction to finite wedges of spheres $S^k$ with $k\leq n$. In particular they are determined by their restriction to finite pointed spaces of homotopy dimension $\leq n$, which is very different from $n$-truncated spaces.
Aug 21, 2021 at 7:38 comment added Marc Hoyois The case $n=0$ is far from true: every 1-excisive functor $\mathrm{Fin}_*\to \mathcal S$ is constant...
Aug 20, 2021 at 22:31 history asked Emily CC BY-SA 4.0