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Mar 9, 2022 at 6:30 history edited Praphulla Koushik CC BY-SA 4.0
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Aug 22, 2021 at 11:18 comment added Denis T Differential graded Lie algebras and Lebniz algebra cohomology, Jacob Mostovoy arxiv.org/abs/1910.03754v1 The paper doesn't mention algebroids, but usual Lie-Reinhart definition of an algebroid translates directly to this setting.
Aug 22, 2021 at 7:35 comment added Praphulla Koushik @DenisT. Can you please give reference for seeing Leibniz algebroids as dg Lie algebroids. Thank you :)
Aug 21, 2021 at 11:48 comment added Denis T Another approach is to regard Leibniz algebroids as acyclic dg Lie algebroids concentrated in degrees 0, 1 and 2. There's an equivalence of categories sending a Leibniz algebra $S$ to a complex with degree 0 equal to liefication of $S$ (quotient by an ideal spanned by $[x, x]$), degree 1 being $S$ and degree 2 the kernel of natural projection. So, you can rewrite that non-skew symmetric bracket as a honest dg Lie bracket.
Aug 21, 2021 at 1:18 answer added AlexArvanitakis timeline score: 1
Aug 20, 2021 at 17:41 history asked Praphulla Koushik CC BY-SA 4.0