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Nov 28 at 21:24 comment added Pietro Majer Yes I think $f$ in the last sentence was assumed to be a Morse function .
Nov 28 at 16:28 comment added Ryan Budney I suspect in Pietro's answer $f$ is assumed Morse.
Nov 25 at 4:34 comment added user527492 I'm not sure I understand your answer as written. If $f = 0$, then there exist $C^2$ functions arbitrarily close in the $C^2$ metric with finitely many critical points.
Aug 20, 2021 at 7:49 history answered Pietro Majer CC BY-SA 4.0