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Aug 14, 2021 at 18:08 history edited Konstantinos Kanakoglou CC BY-SA 4.0
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Aug 12, 2021 at 21:12 vote accept Spyros Olympopolous
Aug 12, 2021 at 21:02 comment added Konstantinos Kanakoglou If we are speaking about HAs then the presence of $1$ makes the connected and the irreducibles the same thing. Since then the trivial (1-dim) comodule always makes sense.
Aug 12, 2021 at 20:57 comment added Konstantinos Kanakoglou @Spyros, a connected coalgebra has a unique simple comodule, which must be 1-dim. An irreducible one has a unique simple comodule. So at the level of coalgebras, connected are irreducibles (but not necessarily the other way around). So the irreducibles are a wider class.
Aug 12, 2021 at 20:33 history edited Konstantinos Kanakoglou CC BY-SA 4.0
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Aug 12, 2021 at 18:12 comment added Spyros Olympopolous Thanks for your answer. Just so I understand precisely - irreducible is a special of connected? Precisely an irreducible Hopf algebras is one that has a single comodule, namely the trivial comodule, and hence it is connected since connected requires the weaker condition of the existence of a single 1-dim comodule. Is this correct.
Aug 12, 2021 at 11:11 history edited Konstantinos Kanakoglou CC BY-SA 4.0
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Aug 12, 2021 at 6:43 vote accept Spyros Olympopolous
Aug 12, 2021 at 6:45
Aug 12, 2021 at 1:07 history answered Konstantinos Kanakoglou CC BY-SA 4.0