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Nov 11, 2010 at 15:21 comment added Steven Gubkin @Jeff: The MO question I linked to shows that for C^\infty functions, these axioms do characterize differentiation.
Nov 4, 2010 at 18:12 comment added Jeff Strom I don't claim these properties fully characterize differentiation. I've toyed with adding a "uniform convergence" type axiom, but not for Calculus 1 purposes. Unfortunately, all of my analysis knowledge is half-remembered, so I'd have to sit down and think about this, and I have not found the time yet.
Nov 4, 2010 at 14:23 comment added Steven Gubkin See this MO question: mathoverflow.net/questions/44774/…
Nov 4, 2010 at 3:01 comment added Steven Gubkin So see that I can get more than polynomials: By using the chain rule and the product rule I can actually get any algebraic function. But I still do not see how to get any transcendental function.
Nov 3, 2010 at 15:41 comment added Steven Gubkin Is there really a unique equivalence relation satisfying these rules? I do not see how these rules could ever access a function which is not a polynomial. If not, saying that you can define f'(a) to be the slope of the tangent line at x=a presupposes that you have chosen one of the many equivalence relations which satisfy these properties.
Oct 19, 2010 at 14:11 history made wiki Post Made Community Wiki by S. Carnahan
Oct 9, 2010 at 1:27 history edited Jeff Strom CC BY-SA 2.5
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Sep 27, 2010 at 17:12 comment added Mark Meckes I second Deane's comment.
Sep 27, 2010 at 14:20 comment added Deane Yang This is very nice.
Sep 27, 2010 at 13:58 history answered Jeff Strom CC BY-SA 2.5