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Apply M"obiusMöbius summation, the formula for $\sum_{n>=1}\cos(2\pi n x)/n^2$ to to obtain $$11/4-45\zeta(3)/\pi^3=1.00543...\;.$$:
$$11/4-45\zeta(3)/\pi^3=1.00543...\;$$
Apply M"obius summation, the formula for $\sum_{n>=1}\cos(2\pi n x)/n^2$ to obtain $$11/4-45\zeta(3)/\pi^3=1.00543...\;.$$
Apply Möbius summation, the formula for $\sum_{n>=1}\cos(2\pi n x)/n^2$ to obtain:
