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Aug 12, 2021 at 21:33 comment added Paul Levy @Callum The centraliser of a regular $\mathfrak{sl} _2$ in a simple Lie algebra is trivial. If $V$ is a simple ${\mathfrak g}$-module then it equals $L(\lambda)$ for some dominant weight $\lambda$, and the action of your regular $h$ tells you the height of $\lambda$. You also know the dimension of $V$, and there can't be too many possibilities for $\lambda$ given this information. However, the action of a regular $\mathfrak{sl} _2$ can't tell the difference between $V$ and $V^*$.
Aug 10, 2021 at 22:14 comment added richrow @JeffreyAdams What exactly I should looking for? As far as I can see they are mostly working with real $\operatorname{SL}_2$.
Aug 10, 2021 at 18:54 comment added Jeffrey Adams See the book Non-Abelian Harmonic Analysis by Roger Howe and Eng-Chye Tan.
Aug 9, 2021 at 14:36 comment added Callum (Very rough musings so take with a pinch of salt). I'm going to assume we know what kind of representation it is (i.e. is it a single irrep or a sum of irreps of certain dimension etc.) . For high enough dimension this is not at all obvious. From there you'll at least need to know the action of the centraliser of $\mathfrak{sl}_2$ since its action will commute. If it is regular this centraliser will be small (indeed I think it is just the orthocomplement of $h$ in the Cartan subalgebra it defines). I don't know if that is enough to fix the action though.
Aug 9, 2021 at 6:33 history edited richrow CC BY-SA 4.0
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Aug 8, 2021 at 16:38 history edited richrow CC BY-SA 4.0
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Aug 8, 2021 at 16:37 comment added richrow @BenMcKay Indeed. I think we should restrict ourselves to the case of simple Lie algebra (actually, the initial motivation was about particular case $\mathfrak{g}=\mathfrak{sl}_{n}$). I will edit the question accordingly.
Aug 8, 2021 at 16:32 history edited richrow CC BY-SA 4.0
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Aug 8, 2021 at 16:28 comment added Ben McKay The Lie algebra $\mathfrak{g}$ could be a sum of some $\mathfrak{sl}_2$ and some arbitrary semisimple Lie algebra, with an arbitrary action on $V$.
Aug 8, 2021 at 16:17 comment added LSpice I think that an example from @DaveWitteMorris is relevant.
Aug 8, 2021 at 16:15 history edited LSpice CC BY-SA 4.0
Missing 'answer'
Aug 8, 2021 at 16:14 comment added LSpice Are you given in advance that the action does extend to $\mathfrak g$, or are you interested in determining whether it extends? (Also, are you working over $\mathbb C$?)
Aug 8, 2021 at 15:40 history asked richrow CC BY-SA 4.0