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Aug 8, 2021 at 4:02 history became hot network question
Aug 8, 2021 at 1:38 vote accept Alexander Woo
Aug 8, 2021 at 1:17 answer added john timeline score: 4
Aug 7, 2021 at 19:03 history edited Alexander Woo CC BY-SA 4.0
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Aug 7, 2021 at 19:01 comment added Alexander Woo @PiotrAchinger - Yes - will edit
Aug 7, 2021 at 19:00 comment added Piotr Achinger Since $Z$ contains the dense open $U$ and $U$ is irreducible, $Z$ is irreducible and hence connected. Did you mean to define $Z = \bigcup_{y\in Y} (\overline{\pi^{-1}(y)} \setminus \pi^{-1}(y))$?
Aug 7, 2021 at 18:51 history asked Alexander Woo CC BY-SA 4.0