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Alexander Woo
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I'm looking for a simple example of the following (so that I can get better intuition for it). If possible, I'd like a 2 dimensional rational example.

$X$ is an irreducible projective variety, with an open subset $U$ that is (isomorphic to) the total space of a line bundle over an irreducible variety - in other words such that there exists an irreducible $Y$ where $\pi: U \rightarrow Y$ is a line bundle. We can look at $Z=\bigcup_{y\in Y} \overline{\pi^{-1}(y)}$$Z=\bigcup_{y\in Y} (\overline{\pi^{-1}(y)}\setminus \pi^{-1}(y))$ (where the closure is taken in $X$) - the union of the closures''limits'' of the fibers of $\pi$. I want an example where $Z$ is not connected.

The intuition is that the ''limit'' of a fiber over a special point $y$ in $Y$ might actually be ''far away'' from the ''limits'' of the fibers of all the points ''close to'' $y$.

I'm looking for a simple example of the following (so that I can get better intuition for it). If possible, I'd like a 2 dimensional rational example.

$X$ is an irreducible projective variety, with an open subset $U$ that is (isomorphic to) the total space of a line bundle over an irreducible variety - in other words such that there exists an irreducible $Y$ where $\pi: U \rightarrow Y$ is a line bundle. We can look at $Z=\bigcup_{y\in Y} \overline{\pi^{-1}(y)}$ (where the closure is taken in $X$) - the union of the closures of the fibers of $\pi$. I want an example where $Z$ is not connected.

The intuition is that the ''limit'' of a fiber over a special point $y$ in $Y$ might actually be ''far away'' from the ''limits'' of the fibers of all the points ''close to'' $y$.

I'm looking for a simple example of the following (so that I can get better intuition for it). If possible, I'd like a 2 dimensional rational example.

$X$ is an irreducible projective variety, with an open subset $U$ that is (isomorphic to) the total space of a line bundle over an irreducible variety - in other words such that there exists an irreducible $Y$ where $\pi: U \rightarrow Y$ is a line bundle. We can look at $Z=\bigcup_{y\in Y} (\overline{\pi^{-1}(y)}\setminus \pi^{-1}(y))$ (where the closure is taken in $X$) - the union of the ''limits'' of the fibers of $\pi$. I want an example where $Z$ is not connected.

The intuition is that the ''limit'' of a fiber over a special point $y$ in $Y$ might actually be ''far away'' from the ''limits'' of the fibers of all the points ''close to'' $y$.

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Alexander Woo
  • 3.1k
  • 1
  • 23
  • 24

Example sought: disconnected closures of fibers of line bundles

I'm looking for a simple example of the following (so that I can get better intuition for it). If possible, I'd like a 2 dimensional rational example.

$X$ is an irreducible projective variety, with an open subset $U$ that is (isomorphic to) the total space of a line bundle over an irreducible variety - in other words such that there exists an irreducible $Y$ where $\pi: U \rightarrow Y$ is a line bundle. We can look at $Z=\bigcup_{y\in Y} \overline{\pi^{-1}(y)}$ (where the closure is taken in $X$) - the union of the closures of the fibers of $\pi$. I want an example where $Z$ is not connected.

The intuition is that the ''limit'' of a fiber over a special point $y$ in $Y$ might actually be ''far away'' from the ''limits'' of the fibers of all the points ''close to'' $y$.