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Aug 8, 2021 at 20:09 vote accept Emily
Aug 7, 2021 at 20:53 answer added Marc Hoyois timeline score: 13
Aug 7, 2021 at 20:37 history edited Emily CC BY-SA 4.0
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Aug 7, 2021 at 20:37 comment added Emily @RuneHaugseng Thanks, this is excellent!
Aug 7, 2021 at 10:48 comment added Rune Haugseng The unit is the free commutative monoid on the point, which is $\coprod_{n=0}^{\infty} B\Sigma_n$, or the groupoid of finite sets and bijections. More generally, Gepner-Groth-Nikolaus show that the free commutative monoid functor $F$ is symmetric monoidal (for the cartesian product of spaces), so for spaces $X,Y$ you have $F(X) \otimes F(Y) \simeq F(X \times Y)$. (In fact, since any commutative monoid is a (simplicial) colimit of free ones, this in a sense determines the tensor product, since it also preserves colimits in each variable.)
Aug 6, 2021 at 23:13 history edited Emily CC BY-SA 4.0
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Aug 6, 2021 at 22:36 history asked Emily CC BY-SA 4.0