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Aug 5, 2021 at 15:50 comment added Connor Mooney @MateuszKwaśnicki: That is a fair point. As Alexandre Eremenko points out in the comments, it could be helpful for the question-asker to clarify what is meant by $u,\,\nabla u$ on $\{y = 0\}$.
Aug 5, 2021 at 14:59 comment added Mateusz Kwaśnicki This $u$ is not even bounded near the origin: $u(0, y) = e^{1/y^2}$, so what would $u_y(0, 0) = 0$ mean?
Aug 5, 2021 at 14:54 history edited Connor Mooney CC BY-SA 4.0
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Aug 5, 2021 at 14:28 history answered Connor Mooney CC BY-SA 4.0