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Feb 14, 2022 at 4:29 vote accept Nico Tripeny
Aug 6, 2021 at 19:26 answer added Will Sawin timeline score: 11
Aug 6, 2021 at 19:06 history edited Will Sawin CC BY-SA 4.0
edited title
Aug 6, 2021 at 17:33 history edited user44143 CC BY-SA 4.0
retitled
Aug 6, 2021 at 17:30 answer added FusRoDah timeline score: 6
Aug 5, 2021 at 16:48 history edited Nico Tripeny CC BY-SA 4.0
Asked about a lower bound as well
Aug 5, 2021 at 14:41 comment added Terry Tao If one draws $d$ uniformly at random amongst the divisors of $n$, then $\log d$ is the sum of independent random variables (coming from each prime power in the factorisation of $n$), and $\sum_{d<n^{1/3}:d|n} 1 / \sum_{d|n} 1$ is the probability that this sum is less than $\frac{1}{3} \log n$. At this point one can apply one's favorite concentration of measure inequality (e.g., Bennett's inequality) to get an upper bound (the best bound to use depends on the regime of parameters such as $n$ or $\sum_{d|n} 1$ that you are most interested in).
Aug 5, 2021 at 6:16 review Close votes
Aug 7, 2021 at 10:41
Aug 5, 2021 at 5:28 history edited Martin Sleziak CC BY-SA 4.0
MathJax: \mid for divisibility
Aug 5, 2021 at 1:56 review First posts
Aug 5, 2021 at 6:00
Aug 5, 2021 at 1:54 history asked Nico Tripeny CC BY-SA 4.0