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Aug 6, 2021 at 18:23 comment added Mike Krebs Wow! Thanks for the rapid and spot-on answer. In case you or anyone else reading this thread is interested, your example shows that $\mathbb{R}$ does not possess a topology which is simultaneously connected, translation-invariant, and irresolvable. (The latter property means, a set and its complement cannot both be dense.) For if it does, then either $A$ or $A^c$ must have nonempty interior, but as you have shown, this will imply that $A$ is clopen.
Aug 6, 2021 at 18:20 vote accept Mike Krebs
Aug 4, 2021 at 10:30 history answered KP Hart CC BY-SA 4.0