Timeline for Vanishing product of polynomials over finite fields
Current License: CC BY-SA 4.0
14 events
when toggle format | what | by | license | comment | |
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Aug 5, 2021 at 4:55 | comment | added | domotorp | @mathworker21 A polynomial depends on a variable if changing the value of the variable might change the value of the polynomial. If a polynomial does not depend on a variable, then it can be expressed without the given variable. | |
Aug 4, 2021 at 21:55 | comment | added | mathworker21 | @domotorp thanks, but I would still like a definition of 'depend'. | |
Aug 4, 2021 at 17:14 | comment | added | domotorp | @mathworker21 The point is that the first part in the product is $x_1+p_1$ where $p_1=-x_2-x_3+x_4$, so $p_1$ does not depend on $x_1$. | |
Aug 4, 2021 at 15:26 | comment | added | mathworker21 | does the polynomial in the very first line 'depend' on $x_1$? | |
Aug 4, 2021 at 15:05 | comment | added | domotorp | Sorry, I've added that too. | |
Aug 4, 2021 at 15:05 | history | edited | domotorp | CC BY-SA 4.0 |
added definition of degenerate
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Aug 4, 2021 at 13:39 | comment | added | Fedor Petrov | I mean, when is a graph called degenerate? | |
Aug 4, 2021 at 13:32 | comment | added | domotorp | I've added the definition to the question, I hope now it's clear. | |
Aug 4, 2021 at 13:32 | history | edited | domotorp | CC BY-SA 4.0 |
added def of dependency graph
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Aug 4, 2021 at 11:14 | comment | added | Fedor Petrov | ok and which graph is degenerate? | |
Aug 4, 2021 at 10:11 | comment | added | Fedor Petrov | Ok, I see (I prefer another notation, but it is a matter of taste.) What do you mean by "dependency graph is degenerate"? | |
Aug 4, 2021 at 9:41 | comment | added | domotorp | I thought that $x^q-x\equiv 0$ over $\mathbb F_q$. So I mean it like that. | |
Aug 4, 2021 at 8:34 | comment | added | Fedor Petrov | by $\equiv 0$ you mean that all values are 0? As a polynomial, this is not identical 0. | |
Aug 4, 2021 at 8:28 | history | asked | domotorp | CC BY-SA 4.0 |