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Jan 30, 2023 at 23:55 vote accept Nate River
Jan 30, 2023 at 20:29 answer added Anton Petrunin timeline score: 3
Aug 3, 2021 at 4:29 comment added Igor Belegradek I should have mentioned that the point of Weyl's paper is that the mixed volumes are independent of the embedding, i.e. they are invariants of the metric on $N$, which is quite remarkable. See also en.wikipedia.org/wiki/Weyl%27s_tube_formula.
Aug 3, 2021 at 4:23 comment added Nate River Wow that’s more complicated than expected. I would hope that taking the limit makes things somewhat easier so we might be able to avoid explicit expressions (for fixed $\varepsilon > 0$, that is).
Aug 3, 2021 at 4:15 comment added Igor Belegradek You may want to check Hermann Weyl's "On the Volume of Tubes", jstor.org/stable/2371513?seq=1#metadata_info_tab_contents. If $M=\mathbb R^n$, then the volume of $N_\varepsilon$ is a degree $n$ polynomial in the variable $\varepsilon$ whose coefficients are mixed volumes of $N$ (up to constant multiples). Weyl gives an explicit formula for the mixed volumes.
Aug 3, 2021 at 2:57 history asked Nate River CC BY-SA 4.0