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Jul 21, 2022 at 18:46 comment added Andrew Hardy What about if you restrict to the positive real numbers, ie $\forall x \in [\delta,1]$? Can you restrict the output of $f$ to be real? Or if not, why not?
Jul 30, 2021 at 12:52 comment added user44143 Thanks! It is a hundred years old but new to me.
Jul 30, 2021 at 12:51 history edited user44143 CC BY-SA 4.0
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Jul 29, 2021 at 23:56 comment added fedja @MattF. The statement is just as I've written. Usually it is stated on the unit circle for the value at $0$: If $F$ is an analytic function in the disk continuous up to the boundary and $L$ is an arc on the unit circumference $\mathbb T$, then $|F(0)|\le [\max_L |F|]^{m(L)}[\max_{\mathbb T\setminus L}|F|]^{1-m(L)}$ where $m(L)=|L|/(2\pi)$. The case of the general simply connected domain with an arbitrary point is obtained by applying a conformal mapping. It is just about subharmonicity of $\log|F|$, nothing fancy. See encyclopediaofmath.org/wiki/Two-constants_theorem
Jul 29, 2021 at 7:35 comment added user44143 Can you provide a statement or reference for the two-constant lemma?
Jul 29, 2021 at 1:37 history answered fedja CC BY-SA 4.0