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Apr 13, 2017 at 12:58 history edited CommunityBot
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Oct 2, 2010 at 19:11 vote accept Martin Brandenburg
Oct 2, 2010 at 18:27 answer added Thomas Nevins timeline score: 9
Sep 29, 2010 at 19:01 answer added Martin Brandenburg timeline score: 12
Sep 29, 2010 at 17:39 comment added Thomas Nevins Gabber's argument also appears in print in Enochs and Estrada, "Relative homological algebra in the category of quasi-coherent sheaves," Adv. in Math. 194 (2005) 284--295.
Sep 29, 2010 at 0:48 comment added BCnrd Martin, good to hear! I probably have the original in a filing cabinet somewhere, but am not sure. If you do get around to typing it up, please email me the .pdf file. Thanks.
Sep 28, 2010 at 14:36 comment added Martin Brandenburg Gabber has sent me a scan of a 11 year old letter, which is addressed to BCnrd ;). I will try to write it up.
Sep 27, 2010 at 14:30 comment added Philipp Hartwig @Bugs Bunny: The first sentence of my comment refers to an earlier version of the question which mentioned the abelian category QCoh(X).
Sep 27, 2010 at 13:13 comment added Martin Brandenburg It's not local. Check the details and you will run into the problems which are solved in the case of concentrated schemes.
Sep 27, 2010 at 12:49 comment added Bugs Bunny @ M.B. Of course you know, this means war! :-) Me thinking that all you need is to distinguish ($af\neq bf$) a pair of distinct morphisms $a,b:X->Y$ by mapping generator to $f:?->X$. Since $a$ and $b$ are distinct, they are distinct on some stalk $X_t$. So all we need is a generator for each $QCoh_t$, of sheaves supported at $t$. But this seems to be a local question, so we are just talking about modules over a local ring, so some appropriate skyscraper is a generator... Have I totally gone mad?
Sep 27, 2010 at 11:53 comment added Martin Brandenburg @Bugs: Homomorphisms on skyscapers only give global sections.
Sep 27, 2010 at 11:05 comment added Bugs Bunny @ Martin B. Doc, you may think it is bonkers but why don't skyscrapers at all the point form a generating set???
Sep 27, 2010 at 11:00 comment added Bugs Bunny @ Phillip H. Non-abelian categories may still have generators. One does not have much to do with another...
Sep 26, 2010 at 18:25 comment added Martin Brandenburg I didn't mean all the details. Anyway, I have emailed Gabber.
Sep 26, 2010 at 15:57 comment added BCnrd Dear Martin: I don't remember how Gabber's argument goes (except that it was "soft", not needing anything deep, just some set-theoretic cleverness -- I think $\kappa$ involves the cardinality of some open affine cover and open affine covers of the double overlaps thereof, and probably other stuff too such as coordinate rings of affine opens), and I don't have time to reconstruct it. I hope someone who is really into such matters may do that, and then they can post it as an appropriate answer. That will be better.
Sep 26, 2010 at 9:46 comment added Martin Brandenburg @Brian: Great. Could you post this as an answer?
Sep 25, 2010 at 14:33 comment added BCnrd There are no counterexamples. For an arbitrary scheme $X$ there exists an infinite cardinal $\kappa$ so that every quasi-coherent sheaf is generated by its quasi-coherent subsheaves of type $\kappa$, where the latter means that sections over some open affine cover (and then necessarily over any open affine) are generated by $\le \kappa$ elements as a module. This was explained to me long ago by Gabber, so ask him for the details. There is obviously a set of isomorphism class representatives for the quasi-coherent sheaves of type $\kappa$, so that settles it affirmatively in general.
Sep 25, 2010 at 14:32 answer added D.-C. Cisinski timeline score: 12
Sep 25, 2010 at 12:43 history edited Martin Brandenburg CC BY-SA 2.5
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Sep 25, 2010 at 12:37 comment added Martin Brandenburg Thank you Philipp ;). The notes of Daniel Murfet are very good (and remind me of the stacks project).
Sep 25, 2010 at 11:43 comment added Philipp Hartwig For a ringed space X the category QCoh(X) need not be abelian. The usual hypothesis on a scheme X which ensures that QCoh(X) is a Grothendieck category is that X be quasi-compact and quasi-separated (this is often called "concentrated"). See [Lipman-Notes on derived functors and Grothendieck duality, 4.1.3.1] (available on his website) for a proof in this case. Also Daniel Murfet's notes are useful and contain a proof, see [therisingsea.org/notes/ModulesOverAScheme.pdf, Proposition 66]. I haven't thought about counterexamples in other cases.
Sep 25, 2010 at 10:47 history asked Martin Brandenburg CC BY-SA 2.5