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Sep 25, 2010 at 14:43 vote accept Maurizio Monge
Sep 25, 2010 at 14:42 comment added Maurizio Monge Seems to be all ok, thanks for the answer. It is indeed easy to verify that the amalgamated products of the two non-abelian $p$-groups of order $p^3$ with $C_{p^2}$ give the same group $(C_p\times C_{p^2})\rtimes C_p$, the action of the last $C_p$ being described as adding $p$ times the first coordinate of the $C_p\times C_{p^2}$ to the second.
Sep 24, 2010 at 20:42 history answered Steve D CC BY-SA 2.5