Timeline for Convergence criterion in the domain of an unbounded operator
Current License: CC BY-SA 4.0
14 events
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| Jul 20, 2021 at 4:20 | vote | accept | Benjamin | ||
| Jul 19, 2021 at 21:20 | comment | added | Jochen Glueck | @LarsvanderLaan: Thanks for the correction! Upvoted. | |
| Jul 19, 2021 at 20:22 | history | edited | Lars | CC BY-SA 4.0 |
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| Jul 19, 2021 at 20:16 | history | edited | Lars | CC BY-SA 4.0 |
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| Jul 19, 2021 at 20:09 | history | edited | Lars | CC BY-SA 4.0 |
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| Jul 19, 2021 at 20:06 | comment | added | Lars | I incorrectly meant strong convergence. I am glad that the proof still goes through mostly unchanged with only weak convergence. Thank you, Michael Renardy. | |
| Jul 19, 2021 at 20:03 | history | edited | Lars | CC BY-SA 4.0 |
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| Jul 19, 2021 at 19:54 | history | edited | Lars | CC BY-SA 4.0 |
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| Jul 19, 2021 at 19:53 | comment | added | Michael Renardy | Weak convergence is enough. SInce the graph of A is closed, it is also weakly closed. | |
| Jul 19, 2021 at 19:34 | comment | added | Jochen Glueck | I'm not sure I follow. Why should boundedness of $(Ax_n)$ imply the existence of a convergent subsequence? Do you mean weakly convergent? | |
| Jul 19, 2021 at 19:00 | history | edited | Lars | CC BY-SA 4.0 |
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| Jul 19, 2021 at 19:00 | history | undeleted | Lars | ||
| Jul 19, 2021 at 18:59 | history | deleted | Lars | via Vote | |
| Jul 19, 2021 at 18:55 | history | answered | Lars | CC BY-SA 4.0 |