Timeline for Linear transport equation with unbounded coefficients
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 18, 2021 at 18:39 | comment | added | Iosif Pinelis | @GiorgioMetafune : Thank you for your comment. | |
| Jul 18, 2021 at 17:53 | vote | accept | Pritam Bemis | ||
| Jul 18, 2021 at 17:33 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 146 characters in body
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| Jul 18, 2021 at 16:59 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 41 characters in body
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| Jul 18, 2021 at 16:34 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
added 425 characters in body
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| Jul 18, 2021 at 16:15 | comment | added | Giorgio Metafune | If you take $q(x)=-x^3$, $p(x)=0$, the solution is $f(t,x)=f_0(\frac{x}{\sqrt{1+2t x^2}})$ which does not decay in $x$ for fixed $t$. | |
| Jul 18, 2021 at 16:07 | comment | added | Pritam Bemis | @GiorgioMetafune actually, it was supposed to be a constant matrix, but it is not necessary, as we can absorb it in $q$, thanks. | |
| Jul 18, 2021 at 16:01 | comment | added | Giorgio Metafune | What is $B$ in the statement? | |
| Jul 18, 2021 at 15:23 | comment | added | Pritam Bemis | hope it is clearer now. | |
| Jul 18, 2021 at 14:51 | comment | added | Iosif Pinelis | Indeed, your question and your comment are different things. | |
| Jul 18, 2021 at 14:47 | comment | added | Pritam Bemis | sorry, perhaps the question was not clear enough: What is meant is: Fix a time $t>0$, then as a function of $x$, does the solution decay faster than any polynomial? This seems to be true in your case for example, as it is just a translation of a Schwartz function. | |
| Jul 18, 2021 at 14:37 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |