Timeline for A property of $C^2$ functions
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| Sep 8, 2021 at 13:46 | comment | added | Iosif Pinelis | @PietroMajer : Good point! | |
| Sep 8, 2021 at 7:59 | comment | added | Pietro Majer | We may also say: since $ f(x)+f'(x)h+Ch^2/2\ge0$ for all $h\in\mathbb R$, as a polynomial in $h$ it has a non-positive discriminant, that is $f'(x)^2\le2Cf(x) $. | |
| Jul 22, 2021 at 10:46 | vote | accept | zhangwei | ||
| Jul 21, 2021 at 2:25 | comment | added | Iosif Pinelis | @ZhangWei : As a new contributor, you may be unfamiliar with these guidelines -- so, just in case: mathoverflow.net/help/someone-answers and mathoverflow.net/help/accepted-answer | |
| Jul 21, 2021 at 1:02 | comment | added | zhangwei | Of course. This is wonderful. | |
| Jul 19, 2021 at 12:34 | comment | added | Iosif Pinelis | @ZhangWei : I am glad you liked this answer. Are you then satisfied with it? | |
| Jul 19, 2021 at 12:16 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jul 19, 2021 at 3:50 | comment | added | zhangwei | Thanks a lot! That's so cool! | |
| Jul 18, 2021 at 17:15 | history | edited | Daniele Tampieri | CC BY-SA 4.0 |
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| Jul 18, 2021 at 14:05 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jul 18, 2021 at 13:57 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jul 18, 2021 at 13:46 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jul 18, 2021 at 13:39 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jul 18, 2021 at 13:32 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jul 18, 2021 at 13:25 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |