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Jun 20, 2022 at 18:46 answer added Yonah Borns-Weil timeline score: 6
Jul 18, 2021 at 18:02 comment added jjcale In practical calculations (e.g. in scattering theory) it might be convenient to work outside $L^{2}$ spaces . But this doesn't mean, that the quantum theory lives outside a Hilbert space. To my knowledge you need a Hilbert space to implement the Born rule.
Jul 18, 2021 at 14:45 comment added Aaron Bergman You’d need rigged Hilbert spaces to explicitly translate that expression into rigorous math, but pretty much anything you can do with it can be understand in terms of the spectral theorem.
Jul 18, 2021 at 4:44 comment added MathMath Aaron, it is not clear to me why the answers to the other post indicate that all this can be translated. For example, it is not clear how the continuous spectrum expansion (\ref{1}) can be justified using, seu, the spectral theorem.
Jul 18, 2021 at 4:42 history edited MathMath CC BY-SA 4.0
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Jul 17, 2021 at 20:01 comment added Aaron Bergman As is indicated in the answer to the other question you asked, this can all be translated into spectral theory of unbounded operators, which is completely rigorous.
Jul 17, 2021 at 19:36 history asked MathMath CC BY-SA 4.0