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Nov 29, 2023 at 14:47 comment added Wolfgang It looks like for each $k$ there is a unique similar polynomial with rational coefficients for the denominator $\binom{kn}{k}\binom{2kn}{kn}2^{kn}$ (and alternating signs for odd $k$), e.g. for $k=4$ $$\log 2=\frac14\sum_{n=1}^{\infty} \frac{(14560 n^3 - 16176 n^2 + 5138 n - 417) }{\binom{4n}4\binom{8n}{4n}2^{4n}} $$ or for $k=5$: $$\log 2=\frac1{40}\sum_{n=1}^{\infty} \frac{(2275625n^4 - 3615750n^3 + 1935175n^2 - 395010n + 23544)(-1)^{n-1} }{\binom{5n}5\binom{10n}{5n}2^{5n}} $$
Aug 15, 2021 at 16:17 vote accept T. Amdeberhan
Jul 18, 2021 at 19:51 comment added Carlo Beenakker these $\log 2$ formulas remind me of the binomial sums for $\pi$, such as $\pi = \sum_{n=0}^\infty \dfrac{50n-6}{{\displaystyle \tbinom{3n}{n}2^{n}}}$
Jul 18, 2021 at 16:13 history edited T. Amdeberhan CC BY-SA 4.0
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Jul 18, 2021 at 15:06 history edited T. Amdeberhan CC BY-SA 4.0
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Jul 18, 2021 at 14:49 history edited T. Amdeberhan CC BY-SA 4.0
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Jul 18, 2021 at 8:26 comment added Nemo This is classical result due to Lehmer: Interesting Series Involving the Central Binomial Coefficient, D. H. Lehmer, The American Mathematical Monthly, Vol. 92, No. 7 (1985), pp. 449-457.
Jul 17, 2021 at 20:08 review Close votes
Jul 20, 2021 at 13:00
Jul 17, 2021 at 19:54 answer added Carlo Beenakker timeline score: 15
Jul 17, 2021 at 19:50 answer added Richard Stanley timeline score: 10
Jul 17, 2021 at 19:46 answer added Noam D. Elkies timeline score: 13
Jul 17, 2021 at 19:37 comment added T. Amdeberhan Your reference gives formulas for series involving zeta functions. Can you point out anything about (2) in the reference?
Jul 17, 2021 at 19:18 history asked T. Amdeberhan CC BY-SA 4.0